1.

The correct statement(s) about Cr^(2+) and Mn^(3+) is(are) [Atomic number of Cr=24 and Mn=25]

Answer»

`CR^(2+)` is a reducing agent
`Mn^(3+)` is an oxidizing agent
Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)` ELECTRONIC configuration
When `Cr^(2+)` is USED as a reducing agent, the chromium ion attains `d^(5)` electronic configuration

Solution :`Cr^(2+)+Mn^(3+)HARR Cr^(3+)+Mn^(2+)`
`Cr^(2+)` is reducing agent `Mn^(3+)` is an OXIDISING agent both `Cr^(2+)` & `Mn^(3+)` exhibit `d^(4)` electronic configuration.


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