1.

The correct statement with regard to H_(2)^(+) and H_(2)^(-) is :

Answer»

both `H_(2)^(+)` and `H_(2)^(-)` do not exist
`H_(2)^(-)` is more stabel than `H_(2)^(+)`
`H_(2)^(+)` is more stable than `H_(2)^(-)`
both `H_(2)^(+)` and `H_(2)^(-)` are equally stable

Solution :`H_(2)^(+),(SIGMA 1 s^(1))`
`:.B.O.=1/2(1-0)=1/2`
`H_(2)^(-):(sigma 1s^(2))(sigma^(***)1s^(1))`
`:.B.O.=1/2(2-1)=1/2`
EVEN THOUGH the bond ordr of `H_(2)^(+)` and `H_(2)^(-)` areequal but `H_(2)^(+)` is more stable than `H_(2)^(-)`are equal but `H_(2)^(+)` is more stable than `H_(2)^(-)` as in th LATTER, an electron is present in the higher energy antibonding `(sigma^(***)1s)` orbital.


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