1.

The correct statements (s) about Cr^(2+) and Mn^(3)is(are) [Atomic numbers of Cr= 24 and Mn= 25]

Answer»

`Cr^(2+)` is a reducing agent
`Mn^(3+0` is an oxidizing agent
Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)`electronic CONFIGURATION
When `Cr^(2+)` is used as a reducing agent, the CHROMIUM ion attains `d^(5)` configuration

Solution :(a) `Cr^(2+)` is a reducing agent as it gets oxidizd to `Cr^(3+) ( 3d^(3)` or `t_(2g)^(3)`which is a stable half-filled configuration)
(b) `Mn^(3+)` is an oxidizing agent asitgets reduced to `Mn^(2+)( 3d^(5)`which is more stablehalf-filledconfiguration ).
(c )`Cr( 24) = 3d^(4) 4s^(2):. Cr^(2+ ) = 3d^(4)`
`Mn(25) = 3d^(5) 4s^(2):.Mn^(3+) = 3d^(4)`
Thus, both `Cr^(2+)` and `Mn^(3+)` have `d^(4)` electronic configuration .
(d) When `Cr^(2+)`is usedas a REDUCINGAGENT, it is OXIDIZED to `Cr^(3+)` which has `d^(3)` and not `d^(5)` configuration.


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