1.

The correct thermodynamic conditions for the spontaneous reaction at all temperature is

Answer»

`DELTAHLT0 and DeltaS=0`
`DELTAHGT0 and DeltaSlt0`
`DeltaHlt0 and DeltaSgt0`
`DeltaHlt0 and DeltaSlt0`

Solution :`DeltaG=DeltaH-T.DeltaS`
For,`DeltaHlt0` and `DeltaSgt0, DeltaG=-ve` (ALWAYS)
`therefore` SPONTANEOUS at all temperatures.


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