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| 1. |
The correctness of equation can be checked using the principle of homogeneity in dimensions. The velocity V of a particle depends on time V as V=At^2+BtFind the dimensions and units of A and B. |
| Answer» SOLUTION :`[A]=[[V]]/[[t^2]]=[[M^0LT^-1]]/[[M^0L^0T^2]]=[M^0LT^-3]` UNIT of`A=ms^-3[B]=[[V]]/[[t]]=[[M^0LT^-1]]/[[M^0L^0T]]=[M^0LT^-2]` Unit `B=ms^-2` | |