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The cost of electricity required to deposit 1 g of Mg is Rs.3.00. The cost of deposit 8 g of Al is (al.mass Al = 27 , Mg = 24)A. Rs.`12.00`B. Rs. `24.00`C. Rs. `32.00`D. Rs.`42.50` |
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Answer» Correct Answer - C `(W_(Al))/(W_(Mg)) = (E_(Mg))/(E_(Al))` `therefore (W_(Al))/(1) = (24//2)/(27//3) = (12)/(9)` `therefore W_(Al) = (12)/(9)` gms. When 1 gm of Mg deposited at the same time , `(12)/(9)` gm of Al deposited by passing same quantity of electricity For 1 gm Mg `-=` it cost three rupees `therefore (12)/(9) g Al -= x : x = (3 xx (12//9))/(1) = 4` rupees `therefore` For 8 gm of Al `-= 8 xx 4 = 32` rupees |
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