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The count of bacteria in a certain experiment was increasing at the rate of 2% per hour. Find the bacteria at the end of 2 hours if the count was initially 500000. |
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Answer» Count of bacteria, P = 500000 Time, n = 2 hours Increasing rate, R = 2% per hour Now, Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest P = Present value R = Annual interest rate n = Time] ∴ Count of bacteria = P (1 + R/100)n = 500000 (1 + 2/100)2 = 500000 (102/100)2 = 500000 × 102/100 × 102/100 = 50 × 102 × 102 = 520200 ∴ Count of bacteria at the end of 2 hours is 520200. |
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