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The coupl acting on a bar magnet of pole strength `2 Am` when kept in a magnetic field of intensity `10 A//m`, such that axis of the magnet makes an angle `30^(0)` with the direction of the field is `80xx10^(-7)Nm`. The distance between the poles of the magnet isA. `(2)/(pi)m`B. `(pi)/(2)m`C. `63.36m`D. `(1)/(2pi)m` |
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Answer» Correct Answer - A `C=MB sin theta` |
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