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The course of an enemy submarine as plotted on a set of rectangular axes is 2x + 3y = 5. On the same axes the course of the destroyer is indicated by x – y = 10. The point (x, y) at which the submarine can be destroyed is : (a) (–7, 3) (b) (–3, 7) (c) (3, –7) (d) (7, –3) |
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Answer» (d) (7, –3) x – y = 10 \(\Rightarrow\) x = y + 10 Substitute this value of x in eqn 2x + 3y = 5. so, that we get the solution. |
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