The `[CrO_(4)^(2-)]` ions are equilibrium for the reaction, `Cr_(2)O_(7)^(2-)+H_(2)Oharr2CrO_(4)^(2-)+2H^(+), "at" pH=4` is:A. `10^(4)[Cr_(2)O_(7)^(2-).K_(c )]^(1//2)`B. `10^(-8)[Cr_(2)O_(7)^(2-)].K_(c )`C. `10^(-4)[Cr_(2)O_(7)^(2-)]^(1//2)`D. `10^(-4)[Cr_(2)O_(7)^(2-)].K_(c _`

The `[CrO_(4)^(2-)]` ions are equilibrium for the reaction, `Cr_(2)O_(

1.	The `[CrO_(4)^(2-)]` ions are equilibrium for the reaction, `Cr_(2)O_(7)^(2-)+H_(2)Oharr2CrO_(4)^(2-)+2H^(+), "at" pH=4` is:A. `10^(4)[Cr_(2)O_(7)^(2-).K_(c )]^(1//2)`B. `10^(-8)[Cr_(2)O_(7)^(2-)].K_(c )`C. `10^(-4)[Cr_(2)O_(7)^(2-)]^(1//2)`D. `10^(-4)[Cr_(2)O_(7)^(2-)].K_(c _`
Answer» Correct Answer - A `K_(c)=([Cr_(2)O_(7)^(2-)]xxK_(c ))/([H^(+)]^(2))=(K_(c )[Cr_(2)O_(7)^(2-)])/((10^(-4))^(2))` `=10^(4)[K_(c )xxCr_(2)O_(7)^(2-)]^(1//2)`

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The `[CrO_(4)^(2-)]` ions are equilibrium for the reaction, `Cr_(2)O_(7)^(2-)+H_(2)Oharr2CrO_(4)^(2-)+2H^(+), "at" pH=4` is:A. `10^(4)[Cr_(2)O_(7)^(2-).K_(c )]^(1//2)`B. `10^(-8)[Cr_(2)O_(7)^(2-)].K_(c )`C. `10^(-4)[Cr_(2)O_(7)^(2-)]^(1//2)`D. `10^(-4)[Cr_(2)O_(7)^(2-)].K_(c _`

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