1.

The crystal field stabilization energy (CFSE) is the highest for

Answer»

`[CoF_4]^(2-)`
`Co(NCS)_4]^(2-)`
`[Co(NH_3)_6]^(3+)`
`[CoCl_4]^(2-)`

Solution :Higher the oxidation state of the METAL, greater the crystal field splitting ENERGY. In options (a) , (B) and (d) , Co is present in +2 oxidation state in (c) it is present in +3 oxidation state and hence has a higher value of CFSE.


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