The currect voltage relation of a diode is given by `1 = (e^(van v//T) – InterviewSolution

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1.	The currect voltage relation of a diode is given by `1 = (e^(van v//T) -1 )mA` where the applied volied `V` is in volts and the tempetature `T` is in degree kelvin if a student make an error meassurting `+- 01 V` while measuring the current of `5 mA at 300 K` what be the error in the value of current in `mA`A. 0.5 mAB. 0.05 mAC. 0.2 mAD. 0.02 mA
Answer» Correct Answer - C Given, `I=(e^(1000V//T)-1) mA` When `I=5mA, then 5=e^(1000V//T)-1` or `e^(1000V//T)=6mA` Now `dI=(e^(1000V//T))xx1000/TdV` `=(6 mA)xx1000/300xx(0.01)=0.2 mA`

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