InterviewSolution
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InterviewSolution
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The current density varies radical distance r as `J=ar^(2)`, in a cylindrical wire of radius R. The current passing through the wire between radical distance `R//3 and R//2` is,A. `(65piaR^(4))/(2592)`B. `(25piaR^(4))/(72)`C. `(65pia^(2)R^(3))/(2938)`D. `(81pia^(2)R^(4))/(144)` |
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Answer» Correct Answer - 1 Current density `J=ar^(2)` C urrent `I=int jdA` `I=int_(R//3)^( R//2) ar^(2)(2pi rdr)` [where dA ` 2pirdr`) `=2pia[(r^(4))/(4)]_(R//3)^(R//2)=(65piaR^(4))/(25892)` |
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