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The current flowing through the X-ray tube which is operating at 25 kV is 1 mA. Calculate the number of electrons hitting target per second . Also, find the energy falling on the target per second. |
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Answer» Current flowing in X-ray tube =1m A Potential difference =25 kV Current (I) is given by I="ne" where, n =number of electrons hitting the target per second. `:. " "n=(I)/(e)=(1xx10^(-3))/(1.6xx10^(-6))=6.25xx10^(15)` Now, the energy falling on the target per second is equal to the power consumed by the X-ray tube i.e.,P=VI Here, `V=24 kV=25xx10^(3)V` `I=1mA=1xx10^(-3)A` `:. " " P=(25xx10^(3))(1xx10^(-3))=25W` |
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