The current growth in two L-R circuits (b) and (c) is as shown in Fig. Let `L_(1), L_(2), R_(1) and R_(2)` be the corresponding values in two circuits. Then A. `R_(1) gt R_(2)`B. `R_(1) = R_(2)`C. `L_(1) gt L_(2)`D. `L_(1) lt L_(2)`

The current growth in two L-R circuits (b) and (c) is as shown in Fig.

1.	The current growth in two L-R circuits (b) and (c) is as shown in Fig. Let `L_(1), L_(2), R_(1) and R_(2)` be the corresponding values in two circuits. Then A. `R_(1) gt R_(2)`B. `R_(1) = R_(2)`C. `L_(1) gt L_(2)`D. `L_(1) lt L_(2)`
Answer» Correct Answer - B::D Steady state current for both teh circuits is same. Therefore, `(V)/(R_1)=(V)/(R_2) or R_(1)=R_(2)` Further `tau_(L_(1)) lt tau_(L_2)` (`tau_(L) = "time costant"`) `(L_1)/(R_1) lt (LL_2)/(R_2) or L_(1) lt L_(2)` `(R_(1)=R_(2))`.

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The current growth in two L-R circuits (b) and (c) is as shown in Fig. Let `L_(1), L_(2), R_(1) and R_(2)` be the corresponding values in two circuits. Then A. `R_(1) gt R_(2)`B. `R_(1) = R_(2)`C. `L_(1) gt L_(2)`D. `L_(1) lt L_(2)`

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