1.

The current I in the circuit is A. 1/45 AB. 1/15 AC. 1/10 AD. 1/5 A

Answer» Correct Answer - C
(c) BC and AC are in series
`:. R_(BCA) = 30 + 30 = 60 Omega`
Now BA and DC are in parallel.
`1/R_(eq) = 1/30 + 1/60 = 90/(30 xx 60)`
`R_(eq) = 20Omega , V = IR`
`rArr I = 2/20 = 0.1 Amp. `


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