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The current I in the circuit is A. 1/45 AB. 1/15 AC. 1/10 AD. 1/5 A |
Answer» Correct Answer - C (c) BC and AC are in series `:. R_(BCA) = 30 + 30 = 60 Omega` Now BA and DC are in parallel. `1/R_(eq) = 1/30 + 1/60 = 90/(30 xx 60)` `R_(eq) = 20Omega , V = IR` `rArr I = 2/20 = 0.1 Amp. ` |
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