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The current passing through a galvanometer is 30 mA, resistance of the galvanometer is 50 Ω and a shunt is 1 Ω is connected to the galvanometer. What is the maximum current that can be measured by this ammeter?(a) 1.53 A(b) 15.3 A(c) 0.153 A(d) 153 AThe question was asked in semester exam.My query is from Moving Coil Galvanometer in chapter Moving Charges and Magnetism of Physics – Class 12 |
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Answer» CORRECT answer is (a) 1.53 A The best I can explain: GIVEN: Ig = 30 mA = 0.03 A; S = 1 Ω; G = 50 Ω Required EQUATION ➔ Maximum current (I) = \( [ \frac {(S + G)}{S} ] \) × Ig I = \( [ \frac {(50 + 1)}{1} ] \) × 0.03 I = 51 × 0.03 I = 1.53 A |
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