1.

The current through a wire depends on time as `I = i_(0) + alphat`, where `i_(0)=10 A and alpha=4 As^(-1)`.Find the charge crossed through a section of the wire in 10 second

Answer» `i=i_(0)+alphat,buti=(dq)/(dt)`
`impliesdq=(i_(0)+alphat)dt`
`q=int_(t=0)^(t=10)dqimpliesq=[i_(0)t+(alphat^(2))/(2)]_(0)^(10)`
`=(10i_(0)+50alpha)=300` coloumb


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