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The current through a wire depends on time as `I = i_(0) + alphat`, where `i_(0)=10 A and alpha=4 As^(-1)`.Find the charge crossed through a section of the wire in 10 second |
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Answer» `i=i_(0)+alphat,buti=(dq)/(dt)` `impliesdq=(i_(0)+alphat)dt` `q=int_(t=0)^(t=10)dqimpliesq=[i_(0)t+(alphat^(2))/(2)]_(0)^(10)` `=(10i_(0)+50alpha)=300` coloumb |
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