The current voltage relation of diode is given by I = (e^(1000V//T) - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring +-0.01 V while measuring the current of 5mA at 300K, what will be the error in the value of current in.

The current voltage relation of diode is given by I = (e^(1000V//T) -

1.	The current voltage relation of diode is given by I = (e^(1000V//T) - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring +-0.01 V while measuring the current of 5mA at 300K, what will be the error in the value of current in.
Answer» `0.5 mA` `0.05 mA` `0.2 mA` `0.02 mA` SOLUTION :`I=(e^(1000V//T)-1)mA....(1)` `:.5mA=e^(1000V//T)mA-1mA` `:.6mA=e^(-1000V//T)mA` `:.dt=e^(1000V//T)mAxx(1000)/(T)DV` `=6mAxx(1000)/(300)xx0.01` `=6xx(10)/(300)` `=0.2 mA`