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The currents in the three branches of a parallel circuit are 3A, 4A and 5A. What is the current leaving it?(a) 0A(b) Insufficient data provided(c) The largest one among the three values(d) 12A |
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Answer» Right answer is (d) 12A For explanation I would say: The total current leaving a node is the same as the current that enters it. Total I=I1+I2+I3=3+4+5=12A. |
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