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The curve that passes through the point `(2, 3)` and has the property that the segment of any tangent to it lying between the coordinate axes is bisected by the point of contact, is given byA. `y=(6)/(x)`B. `x^(2)+y^(2)=13`C. `((x)/(2))^(2)+((y)/(3))^(2)=2`D. `2y-3x=0` |
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Answer» Correct Answer - A Let `P(x,y)` be any point on the curve. The equation of tangent at P is givne by `Y-y=(dy)/(dx)(X-x)` This cute coordinate axes at `A(x-y(dx)/(dy),0) and B(0,y-x(dy)/(dx))` It is given that `P(x,y)` is the mid-point of AB. `therefore" "2x=x-y(dx)/(dy)and 2y=y-x(dy)/(dx)` `rArr" "(dy)/(dx)=-(y)/(x)` `rArr" "xdy+ydx=0rArrd(xy)=0rArrxy=C` The curve passes through (2,3). `therefore" "2xx3=CrArr C=6.` The equation of the curve is xy = 6 or, `y=(6)/(x)`. |
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