1.

The curve that passes through the point `(2, 3)` and has the property that the segment of any tangent to it lying between the coordinate axes is bisected by the point of contact, is given byA. `y=(6)/(x)`B. `x^(2)+y^(2)=13`C. `((x)/(2))^(2)+((y)/(3))^(2)=2`D. `2y-3x=0`

Answer» Correct Answer - A
Let `P(x,y)` be any point on the curve. The equation of tangent at P is givne by
`Y-y=(dy)/(dx)(X-x)`
This cute coordinate axes at `A(x-y(dx)/(dy),0) and B(0,y-x(dy)/(dx))`
It is given that `P(x,y)` is the mid-point of AB.
`therefore" "2x=x-y(dx)/(dy)and 2y=y-x(dy)/(dx)`
`rArr" "(dy)/(dx)=-(y)/(x)`
`rArr" "xdy+ydx=0rArrd(xy)=0rArrxy=C`
The curve passes through (2,3).
`therefore" "2xx3=CrArr C=6.`
The equation of the curve is xy = 6 or, `y=(6)/(x)`.


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