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The cycle is shown in figure is made of one mole of perfect gas in a cylinder with a piston . The processes A to B and C to D are isochoric wheras process B to C and D to A are adiabatic, the work done in one cycle is (V_(A)=V_(B)=V,V_(C)=V_(D) =2V "and " gamma=5//3) |
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Answer» `[1-4^(3)/(2)](P_(B)-P_(A))V` |
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