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The cylindrical tube of a spray pump has a cross -section of 8.0cm^(2) one end of which has 40 fine holes each ofdiameter 1.0mm . If the liquid flow inside the tube is 1.5mmin^(-1) , what is the speed of ejection of the liquid through the holes ? |
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Answer» SOLUTION :CROSS section area of pipe `A_(1)=8xx10^(-4)m^(2)` and speed `v_(1)=(1.5)/(60)ms^(-1)=0.025ms^(-1)` Area of holes at the end of other tube =40 `therefore` Area of cross section at other end , `A_(2)=40A` `=40pixx25xx10^(-8)m^(2)`and the speed of liquid at other end `v_(2)`=? From equation of CONTINUITY , `A_(1)v_(1)=A_(2)v_(2)` `8xx10^(-4)xx0.025=40xx3.14xx25xx10^(-8)xxv_(2)` `thereforev_(2)=(8xx10^(-4)xx0.025)/(40xx3.14xx25xx10^(-8))` `=0.00006369xx10^(-8)``=0.00006369xx10^(-4)` `thereforev_(2)=0.64ms^(-1)` |
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