Saved Bookmarks
| 1. |
The cylindrical tube of a spray pump has radius R, one end of which has 'n' fine holes, each of radius r. If the speed of the liquid in the tube is V, what is the speed of the ejection of the liquid through the holes. |
|
Answer» Solution :LET the required SPEED by `v.` ACCORDING to equation of CONTINUITY `a.v. = av` `v. = (av)/(a.) = (piR^2 V)/(n pi r^2) implies v. = (R^2v)/(nr^2)`. |
|