1.

The data given below are for the reactionof NO and Cl_(2) to form NOCl at 295 K [Cl_(2)]""[NO]"""initial rate(mol litre"^(-1)"sec"^(-1)) 0.05""0.05""1xx10^(-3) 0.15""0.05"3xx10^(-3) 0.05""0.15""9xx10^(-3) The reaction rate when conc. of Cl_(2) an NO are 0.2 M and 0.4 M respectively is

Answer»

0.256 MOLE `"litre"^(-1)`
0.256 mole `"litre"^(-1)"sec"^(-1)`
0.512 mole litre `"sec"^(-1)`
0.512 mole `"litre"^(-1)`sec

Solution :`r=K[NO]^(2)[Cl_(2)]^(1)=8XX(0.4)^(2)XX(0.2)^(1)=8xx0.4xx0.4xx0.2=0.256`


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