1.

The dcecomposition of a substance follows first order kinatics. Its concentraction is reduced to (1)/(8)th of its initial value in 24 minutes. The rate constant of the decomposition process is

Answer»

`(1)/(4)mi N^(-1)`
`(0.692)/(24)MOL^(-1)`
`(2.303)/(24)"LOG"((1)/(8))mi n^(-1)`
`(2.303)/(24)"log"((8)/(1)mi n^(-1)`

SOLUTION :`k=(2.303)/(t)"log"(a)/(a-x)=(2.303)/(24)"log"((1)/((1)/(8)))=(2.303)/(24)"log"8`


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