1.

The de Broglie wavelength of an electron is 66 nm. The velocity of the electron is (h=6.6xx10^(-34)kgm^(2)s^(-1)m=9.0xx10^(-31)kg)

Answer»

`1.84xx10^(-14)ms^(-1)`
`1.1xx10^(-4)ms^(-1)`
`5.4 XX 10^(3)ms^(-1)`
`1.1xx10^(4)ms^(-1)`

Solution :`lamda=h/(mv)=(6.6xx10^(-34))/(9.0xx10^(-31)xx66xx10^(-9))`
`=1.1xx10^(4)ms^(-1)`


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