1.

The decomposition of a certain mass of CaCO_(3) gave 11.2 dm^(3) of CO_(2) gas at STP. The mass of KOH required to completely neutralise the gas is:

Answer»

56g
28g
42g
20g

Solution :`11.2dm^(3)` of `CO_(2)` at `STP=(1)/(2)"MOLE"CO_(2)`
`KOH+CO_(2)rarrKHCO_(3)`
`(1)/(2)` mole `CO_(2)` will be neutralised by `(1)/(2)` mole KOH,i.e.,28g KOH


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