The decomposition of A into product has value of k as 4.5xx10^(3) s^(-1) at 10^(@)C and energy of activation 60 KJ mol^(-1) .at what temperature would k be 1.5xx10^(4)s^(-1)?

The decomposition of A into product has value of k as 4.5xx10^(3) s^(-

1.	The decomposition of A into product has value of k as 4.5xx10^(3) s^(-1) at 10^(@)C and energy of activation 60 KJ mol^(-1) .at what temperature would k be 1.5xx10^(4)s^(-1)?
Answer» Solution :REACTION A `to` Product `T_(1)=10^(@)C=10+273=283 K` and `K_(1)=4.5xx10^(3)s^(-1)` `E_(a)=60 KJ mol^(-1)=60000J mol^(-1)` If `K_(2)=1.5xx104 s^(-1)` so temperature `T_(2)`=(?) The ARRHENIUS equation is as under. log `(K_(1))/(K_(2))=(E_(a))/(2.303)((T_(2)-T_(1))/(T_(1)T_(2)))` `therefore ((1.5xx10^(4))/(4.5xx10^(3)))=(60000 J mol^(-1))/(2.303xx(8.314 JK^(-1) mol^(-1)))((T_(2)-283)/(T_(2)xx283))` `therefore log 0.5228=(6000K)/(2.303xx8.314)((T_(2)-283)/(283 T_(2)))` `therefore (T_(2)-283)/(T_(2))=(0.5228xx2.303xx8.314xx283)/(60000)` `therefore T_(2)-283=(0.0472)T_(2)` `therefore (T_(2)-0.0472 T_(2))=283` `therefore 0.9528 T_(2)=283` `therefore T_(2)=(283)/(0.9528)=297.02 K=24.02^(@)`C