The decomposition of A into product has value of k as `4.5 xx10^(3) s^(-1)at 10^(@)C` and energy of activation `60 kJ mol ^(-1).` At what temperature would k be `1.5 xx10^(4) s^(-1)?`

The decomposition of A into product has value of k as `4.5 xx10^(3) s^

1.	The decomposition of A into product has value of k as `4.5 xx10^(3) s^(-1)at 10^(@)C` and energy of activation `60 kJ mol ^(-1).` At what temperature would k be `1.5 xx10^(4) s^(-1)?`
Answer» According to Arrhenius equation `log ""(k_(2))/(k_(1))=(E_(a))/(2.303R)xx(T_(2)-T_(1))/(T_(1)T_(2))` `k_(1)=4.5xx10^(3)s^(-1)` `k_(2) =1.5 xx10^(4)s^(-1)` `T_(1)=10^(@)C=283K` `log ""(1.5 xx10^(4))/(4.5xx10^(3))=((6000Jmol ^(-1)))/(2.303 xx(8.314J mol ^(-1)))=((T_(2)-283)/(283T_(2)))` `log 3.333 =3133.62 (T_(2)-283)/(283T_(2))` `1-(283)/(T_(2))=0.04776` `or T_(2)=(283)/(1-0.04776)=(283)/(0.9524)` ` T_(2) =297.19 K =(297.19-273.0)=24.19^(@)C` Temperature `=24.19^(@)C`

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The decomposition of A into product has value of k as `4.5 xx10^(3) s^(-1)at 10^(@)C` and energy of activation `60 kJ mol ^(-1).` At what temperature would k be `1.5 xx10^(4) s^(-1)?`

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