The decomposition of dimethyl ether leads to the formation of CH_(4), H_(2) and CO and the reaction rate is given by Rate =k[CH_(3)OCH_(3)]^(3//2) The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., Rate =k(p_(CH_(3)OCH_(3)))^(3//2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

The decomposition of dimethyl ether leads to the formation of CH_(4),

1.	The decomposition of dimethyl ether leads to the formation of CH_(4), H_(2) and CO and the reaction rate is given by Rate =k[CH_(3)OCH_(3)]^(3//2) The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., Rate =k(p_(CH_(3)OCH_(3)))^(3//2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?
Answer» Solution :In TERMS of pressures, units of rate = bar minutes`""^(-1)` Units of `K=("Rate"("bar minutes"^(-1)))/([p_(CH_(3)OCH_(3))]^(3//2)("bar"^(3//2)))="bar"^(-1//2)"minutes"^(-1)`.