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The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T). Calculate E_(a). |
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Answer» Solution :Given that `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)` According to Arrhenius EQUATION, `k=Ae^(-E_(a)//RT)` EQUATING SIMILAR terms `-(E_(a))/(RT)=(28000K)/(T)` or `E_(a)=28000 K xx R=28000 K xx 8.314 JK^(-1)"mol"^(-1)=232.79"KJ mol"^(-1)`. |
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