1.

The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)` Calculate `E_(a)`.

Answer» Correct Answer - `232.79kJ mol^(-10`
According to Arrhenius equation `k=Ae^(-Ea//RT)`
`:. (-E_(a))/(RT)=-(28000K)/(T)`
or `E_(a)=28000KxxR`
`=28000Kxx8.314K ^(-1) mol^(-1)=232.79 kJ mol^(-1)`


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