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The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)` Calculate `E_(a)`. |
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Answer» Correct Answer - `232.79kJ mol^(-10` According to Arrhenius equation `k=Ae^(-Ea//RT)` `:. (-E_(a))/(RT)=-(28000K)/(T)` or `E_(a)=28000KxxR` `=28000Kxx8.314K ^(-1) mol^(-1)=232.79 kJ mol^(-1)` |
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