1.

The decomposition of N_(2)O_(4) to NO_(2) is carried out at 280K in chloroform. When equilibrium has been estabilished, 0.2 mol of N_(2)O_(4) and 2xx10^(-3)mol of NO_(2) are present in 2 litre solution. The equlibrium constant for reaction N_(2)O_(4)hArr 2NO_(2) is

Answer»

`1xx10^(-2)`
`2xx10^(-3)`
`1xx10^(-5)`
`2xx10^(-5)`

Solution :`K=([NO_(2)]^(2))/([N_(2)O_(4)])=([2xx(10)/(2)^(-3)]^(2))/([(2)/(2)])=(10^(-6))/(10^(-1))=10^(-5).`


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