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The decomposition of NH₃ on platinum surface is zero order reaction. What are the rates of production of N₂ and H₂ respectively if k = 2.5 × 10⁻⁴ mol⁻¹ L s⁻¹? *(a) 2.5 × 10⁻⁴ molL⁻¹ s⁻¹and 7.5 × 10⁻⁴ molL⁻¹ s⁻¹(b) 5.5 × 10⁻⁴ molL⁻¹ s⁻¹and 7.5 × 10⁻⁴ molL⁻¹ s⁻¹(c) 7.5 × 10⁻⁴ molL⁻¹ s⁻¹and 2.5 × 10⁻⁴ molL⁻¹ s⁻¹(d) 8.5 × 10⁻⁴ molL⁻¹ s⁻¹and 7.5 × 10⁻⁴ molL⁻¹ s⁻¹ |
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Answer» 2NH 3Pt N 2 +3H 2 Rate=− 21[ dtd[NH 3 ] ]=[ dtd[N 2 ] ]=+ 31 [ dtd[H 2 ] ] As the order of the reaction is zero HENCE rate of reaction Rate of reaction = k Rate of production of N 2= 2.5×10 −4molL −1 s −1
Rate of production OFH 2 =3×2.5×10 −4 =7.5×10 −4 molL −1 s −1 mark me as brainlist |
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