InterviewSolution
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InterviewSolution
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The degree of dissociation is 0.4 at 400 K and1.0 atm for the gaseous reactions C2. Assuming ideal behaviour of all the gases, calculate the denr and 1.0 atmosphere. (Atomic mass of P-31.0 and Cl - 35.5)mixture |
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Answer» PCI5 ⇌ PCI3 + CI2Initial moles 1 0 0Moles at eq 1 -0.4 0.4 0.4∴ Total moles at equilibrium = 1 – 0.4 + 0.4 + 0.4 = 1.4Also Normal mol. Wt. of PCI5/Exp. Mol. Wt. of PCI5 = 1 + ∝ = 1.4Or 208.5/Exp. mol. Wt. of PCI5 = 1.4∴ Exp. mol. Wt. of PCI5 or m. wt. of mixture = 208.5/1.4Now using, PV = w/m RT for mixtured = w/V = Pm/RT = 1 * 208.5/1.4 *0.082 *400 = 4.53 g/litre |
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