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The degree of dissociation of an acid HA in 0.1 M solution is 0.1%. Its dissociation constant is |
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Answer» Solution :`k_a= Calpha^2` Since dissociation constant of acid, `K_a` is constant, `alpha ` depends UPON concentration. ` alpha^2 PROP (1)/(c )oralphaprop (1)/( sqrt(C )) or (alpha_2)/(alpha_1)= sqrt((c_1)/(c_2))` SUBSTITUTING the VALUES,`(alpha_2)/(0.006) = sqrt((0.1 )/( 0.05 ) )= sqrt(20)` solving thevalues`alpha_2= 0.006 xx sqrt(20 ) ` thedgreeof dissociationin 0.05Msolutionis `0.027` |
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