The degree of dissociation of N_(2) O_(2) into NO_(2) at one atmosphere and 40^(@)C is 0.310. For this :

The degree of dissociation of N_(2) O_(2) into NO_(2) at one atmospher

1.	The degree of dissociation of N_(2) O_(2) into NO_(2) at one atmosphere and 40^(@)C is 0.310. For this :
Answer» `K_(P)` = 0.42 atm `K_(c)` = 0.003 mole `lit^(-)` Degree of dissociation at 10 atm pressure at same temperature `alpha` = 0.1025 Degree of dissociation (`alpha`) decreases with increase pressure a given temperature Solution :`underset(underset(0.7)(1-0.3))underset(1)(N_(2)O_(4(g))) harr underset(underset(0.6)(0.6))underset(0)(2NO_(2(g)))` Total moles = 0.7 +0.6=1.3 `Kp=(P^(2)NO_(2))/(PN_(2)O_(4))=(((0.6)/(1.3))^(2))/((0.7)/(1.3))=(0.6 xx 0.6)/(1.3 xx 0.7)` `=0.4 atm implies Kp=Kc(RT)^(Delta n_((g)))`