The degree of hardness of a given sample of hard water is 40 ppm. If the entire hardness in due to MgSO_(4) , how much of MgSO_(4) is present per kg of water ?

The degree of hardness of a given sample of hard water is 40 ppm. If t

1.	The degree of hardness of a given sample of hard water is 40 ppm. If the entire hardness in due to MgSO_(4) , how much of MgSO_(4) is present per kg of water ?
Answer» Solution :Degree of HARDNESS of `H_(2)O` is 40 ppm, i.e., `10^(6)` g of water contain `CaCO_(3)`=40 g Since 1 MOLE of `CaCO_(3)-=1 `mole of `MgSO_(4)` `therefore 100 ` g of `CaCO_(3)-=120` g of `MgSO_(4)` `therefore10^(6)` g of water contain `MgSO_(4)=(40xx120)/(100)=48 g` or `10^(3)` g of water contain `MgSO_(4)=(48xx10^(3))/(10^(6))xx10^(3) ` MG or 1 kg of water will contain `MgSO_(4)=48` mg