1.

The degree of hydrolysis in hydrolic equilibrium A^(-) + H_(2)O hArr HA + OH^(-) at salt concentration of 0.001 M is (K_(1) = 1 xx 10^(-5))

Answer»

`1 xx 10^(-3)`
`1 xx 10^(-4)`
`5 xx 10^(-4)`
`1 xx 10^(-6)`

SOLUTION :`K_(h) = (K_(w))/(K_(a)) = (10^(-14))/(1 xx 10^(-5)) = 10^(-9)`
`K_(h) = alpha^(2)C, alpha = sqrt((K_(h))/(C)) = sqrt((1 xx 10^(-9))/(0.001)) = 1 xx 10^(-3)`.


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