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The degree of ionisation of an acid HA is 0.00001 at 0.1 M concentration. Its dissociation constant will beA. `10^(-9)`B. `10^(-11)`C. `10^(-8)`D. `10^(-7)` |
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Answer» Correct Answer - B `K_(a)=calpha^(2)=0.1xx(10^(-5))^(2)=10^(-11)` |
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