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The degree of ionization of a 0.1M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the `pK_(a)` of bromoacetic acid. |
Answer» Correct Answer - `pH = 1.88, pK_(a) = 2.70` Degree of ionization, `alpha` = 0.132 Concentration, `c = 0.1 M` Thus, the concentration of `H_(3)O+ = c.alpha` `= 0.1 xx 0.132` `= 0.0132` `pH = -"log"[H^(+)] ` `= -log (0.0132)` `= 1.879 : 1.88` Now, `K_(a) = Calpha^(2)` `= 0.1 xx (0.132)^(2)` `K_(a) = .0017` `pK_(a) = 2.75` |
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