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The dehydrobromination of 2bromobutane give `CH_(3) CH=CHCH_(3)` The product is .A. Hofmann productB. Saytzeff productC. Hoffmann-Saytzeff productD. Markownikoff product

Answer» Correct Answer - B
`CH_(3) -underset(Br)underset(|)CH-CH_(2) -CH_(3) + underset((alc))KOH overset("Saytzeffs rule")rarr`
`CH_(3) -CH=CH-CH_(3) +KBr +H_(2)O` .


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