1.

The Delta_(i)H_1) andDelta_(i) H_(2) of Mg(g ) are740and 1450 kJ mol^(-1). Calculatethe percentageof Mg^(+) ( g) andMg^(2+) ( g) if 1 g ofMg ( g)absorbs 50kj of energy .

Answer»

Solution :No . Of moes of Mgvapourspresent in1 g =`1//24 = 0.0417`
Energy absorbed inthe ionizationof 0.0417mole ofMg ( g) to `MG^(2+) ( g) =0.0417xx 740= 30. 83 KJ`
Energyleftunused= 50- 30. 83= 19 . 17kj
Now 19. 17 kjwill be usedto ionize `Mg^(+)( g) ` to `Mg^(2+)` ( g)
`:. ` No. of moles of `Mg^(+)(g )`convertedinto `Mg^(2+) ( g) = 19. 17 // 1450= 0.0132`

No. ofmoles ofmagnesium ionsleft as `Mg^(+) ( g) =0.0417-0.0417-0.0132= 0.0285`
`:. ` %ageof `Mg^(+) (g)= (0.0285// 0.0417 ) xx 100 =68.35 %` and% ageof `Mg^(2+) ( g) =100-68 . 35 = 31 .65 %`


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