1.

The DeltaH and DeltaS for a reaction at one atmospheric pressure are +30.558 kJ and 0.066 kJk^(-1) respectively. The temperature at which the free energy change will be zero and below of this temperature the nature of reaction would be

Answer»

483 K, spontaneous
443 K, non-spontaneous
443 K, spontaneous
463 K, spontaneous

SOLUTION :`DeltaG=DeltaH-TDeltaS`
`0=+30.558-Txx0.066`
`or T=(30.558)/(0.066)=463 K`
If `(dG)_(T,P)=0` sign '=' mean. It is REVERSIBLE PROCESS.


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