1.

The DeltaH^(@) for CO_(2)(g), CO(g) and H_(2)O(g) are -393.5, -110.5 and -241.8 kJ mol^(-1) respectively.The standard enthalpy change (in kJ) for the reaction : CO_(2)(g) + H_(2)(g) to CO(g) + H_(2)O(g) is

Answer»

524.1
41.2
`-262.5`
`-41.2`

Solution :`DELTAH ^(@) = Delta_(f)H^(@)(CO)+ Delta_(f)H^(@)(H_(2)O) - Delta_(f)H^(@)(CO_(2)) - Delta_(f)H^(@)(H_(2))`
= `110.5 + (-241.8) -(-393.5) -0`
`= 41.2 KJ`


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