1.

The densities of three gases O_2,SO_2 and H_2 are measured at 400 K and 1 atm.They are 0.8g//L,32/15g//L and 1/25g//L respectively.Which of the following statements is/are correct for these gases ? (Use R=1/12L atm//mol-K).

Answer»

`SO_2` is SHOWING negative deviation from IDEAL behaviour
`O_2` is more compressible than ideal gas under these conditions
`H_2` is BEHAVING ideally
Boyle's temperature of `O_2` is less than 400K.

Solution :`d=(PM)/(ZRT) or Z=(PM)/(dRT)`
`implies Z_(O_2)=(1xx32)/(0.8xx1/12xx400)=1.2` (positive deviation, so less compressible than ideal gas)
` Z_(SO_2)=(1xx64)/(32/15xx1/12xx400)=0.9` (negative deviation)
`Z_(H_2)=(1xx2)/(1/25xx1/12xx400)=1.5` (positive deviation from ideal gas)
1 atm is a low pressure, and at 400K , `Z_(O_2)` is greater than 1.Hence `Z_(O_2)` will be equal to 1 at temperature lower than 400K. Hence Boyle's temperature of `O_2` will be less than 400 K.


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