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The densities of water and isopropyl alcohol are 0.9982 and 0.7887 g/cc. At 20°C, isopropyl alcohol flowed through a viscometer in 624 s and an equal volume of water flowed through the same viscometer in 200 s. If eta (water) = 1.009 xx 10^(-3) Nm^(-2)s,calculate eta (isopropyl alcohol) at 20°C. |
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Answer» Solution :We have, `eta_(1)/eta_(2) = (t_(1)d_(1))/(t_(2)d_(2))` Suppose that .Y and .2. STAND for alcohol and WATER respectively, `therefore eta_(1) = (624 XX 0.7887)/(200 xx 0.9982) xx (1.009 xx 10^(-3))` `=2.487 xx 10^(-3) Nm^(-2) s` |
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