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The density at `20^(@)C` of a 0.5 solution of acetic acid in water is `1.0042` g/m L. The molality of the solutionA. `0.50m`B. `0.613m`C. `0.513m`D. `0.48m` |
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Answer» Correct Answer - C Let , volume of solution `=1000m L` Moles of solute `=0.5` `therefore` Weight of acetic acid `=0.5xx60g=30g` Mass of solution = volume of solution x density `therefore = 1000m L xx1.0042g//m L ` `therefore` Mass of solution `=1004.2g` Mass of solvent `=1004 .2g-30g` `therefore =974.2g` Molality `=(1000xx"moles of solute")/("mass of solvent")=(1000xx0.5)/(974.2)` `therefore` Molality `=0.513 m` |
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