1.

The density( in g mL^(-1) ) of 3.60sulphuric acid solution that is 29 % H_(2)SO_(4) (Molar mass = 98 g mol^(-1) )by ,mass will be

Answer»

1.64
1.88
1.22
1.45

Solution :`M= 3.6 mol L^(-1)`
`:.` 3.6 mole `H_(2)SO_(4)` in 1000 ML solution
`:.` 1000 mL solution of `H_(2)SO_(4)` contains
`(3.6xx98) g ` of `H_(2)SO_(4)`
The solution is 29% by MASS
`1:.` 100 g solution contains 29 g of `H_(2)SO_(4)`
`:.` If `H_(2)SO_(4) 3.6 xx 98 g`
WEIGHT of solution `= (3.6xx 98xx 100)/(29)` g
Density (d) `= ("wt of solution")/("volume of solution")`
`= (3.6xx 98xx100)/(29 xx 1000) = (3.6xx98)/(290)`
`= 1.2166`
`= 1.22 g mL^(-1)`


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