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The density( in g mL^(-1) ) of 3.60sulphuric acid solution that is 29 % H_(2)SO_(4) (Molar mass = 98 g mol^(-1) )by ,mass will be |
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Answer» 1.64 `:.` 3.6 mole `H_(2)SO_(4)` in 1000 ML solution `:.` 1000 mL solution of `H_(2)SO_(4)` contains `(3.6xx98) g ` of `H_(2)SO_(4)` The solution is 29% by MASS `1:.` 100 g solution contains 29 g of `H_(2)SO_(4)` `:.` If `H_(2)SO_(4) 3.6 xx 98 g` WEIGHT of solution `= (3.6xx 98xx 100)/(29)` g Density (d) `= ("wt of solution")/("volume of solution")` `= (3.6xx 98xx100)/(29 xx 1000) = (3.6xx98)/(290)` `= 1.2166` `= 1.22 g mL^(-1)` |
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